ÎïÖÊ»ºÂýµØÎüÊÕ¿ÕÆøÖеÄË®·Ö£¬»òË®·ÖÖÐË®ÕôÆø±»¾§×´¹ÌÌåÎüÊÕ£¬Ö±µ½½á¾§ÈܽâΪ±¥ºÍÈÜÒºµÄÏÖÏ󣬳ÆÎª³±½â¡£´ÓÈÈÁ¦Ñ§½Ç¶È¿´£¬³±½âµÄÌõ¼þÊÇ¿ÕÆøÖÐË®ÕôÆøµÄÆøÑ¹³¬¹ý±¥ºÍÑÎÈÜÒºÖÐË®·ÖµÄÕôÆøÑ¹¡£Í¨³££¬¸ß¶ÈË®ÈÜÐÔµÄÎïÖÊÓнϴóµÄ³±½âÇ÷ÊÆ£¬ÒòΪŨÈÜÒº¾ß½ÏµÍµÄÕôÆøÑ¹¡£ÀýÈçÔÚ25¡æÊ±£¬´¿Ë®µÄÕôÆøÑ¹Îª 3.12kPa£¬¶ø CaC12·6H2O±¥ºÍÈÜÒºµÄÕôÆøÑ¹½ö0.93kPa¡£ÎïÖʳ±½âµÄËÙ¶ÈÃ÷ÏÔµØÊܵ½ÎïÖʱ©Â¶µÄ±íÃæ»ý£¨Èç½á¾§´óС£©¡¢Ë®ÕôÆøÀ©É¢µ½¾§¸ñµÄËÙÂÊ¡¢¿ÕÆøÖÐÏà¶Ôʪ¶È¼°ÆäËûÒòËØµÄÖÆÔ¼£¬ÈÝÒ׳±½âµÄÎïÖÊÓÐCaC12¡¢MgC12 FeC13 AIC13¡¢NaOHµÈÎÞ»úÑΡ¢¼î¡£Ò׳±½âµÄÎïÖʳ£ÓÃ×÷¸ÉÔï¼Á£¬ÒÔÎüÊÕÒºÌå»òÆøÌåµÄË®·Ö¡£Ò׳±½âµÄÎïÖʱØÐëÔÚÃܱÕÌõ¼þϱ£´æ£»Ò׳±½âµÄÒ©Îï£¨ÌØ±ðÊÇÔÁÏÒ©£©¸üÒªÔÚ·À³±Ìõ¼þÏÂÖü´æ£¬ÒÔ·ÀùÀñäÖÊ¡£